Study guides

Q: What number can be divided by two with a remainder of 1?

Write your answer...

Submit

Related questions

58

17

Every 2 digit number, when divided by the number one less than it, will result in a remainder of 1.

Odd

A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.A modulus is the remainder after a number has been divided into another. 3 divides into 10 with a remainder of 1. So 1 is the modulus of 10 divided by 3.

A 2 digit number divided by a four digit number, such as 2345, will leave the whole 2-digit number as a remainder. It cannot leave a remainder of 1.

solve it with a calculater

3 divided by 2 has a remainder of 1. Which is 1 less than 2.

61,121,181,241,301,361,421,481,541,601,661,721,781,841,901,961,1021,1081,1141,1201, ect

The LCM of 2, 3, 4 and 5 is 60. Since you need a remainder of 1 just add 1. So the answer is 61. Or any number that is 1 more than a multiple of 60.

59

29

85. A number when divided by 238, leaves a remainder 79. What will be the remainder when the number is divided bv 17 ? (1) 8 (2) 9 (3) 10 @) 11

57

24

Put the remainder over the number you originally divided by. 15 divided by 7 = 2, remainder 1 = 2 and 1/7

4

No number can satisfy these conditions: To have a remainder of 1 when divided by 6, the number must be odd (as all multiples of 6 are even and an even number plus 1 is odd) To have a remainder of 2 when divided by 8, the number must be even (as all multiples of 8 are even and an even number plus 2 is even) No number is both odd and even. → No number exists that has a remainder of 1 when divided by 6, and 2 when divided by 8.

301 is one such number.

8

An even number can be divided by 2 evenly. An odd number will have a remainder of 1 when divided by 2. 2 is always even.

7, 37, 67, 97, 127, and an infinite number of other numbers in this series (starting with 7 and increasing in increments of 30) have a remainder of 1 when divided by 6 and a remainder of 2 when divided by 5.

I think you're wanting a number of two digits, one of which is 3, that when divided by 7 gives a quotient and a remainder of 1 and when that quotient is divided by 2 it gives a remainder of 1: Answer: 36 36 ÷ 7 = 5 r 1 5 ÷ 2 = 2 r 1 If you want the number to be such that if it is divided by 7 the remainder is 1 and if it is divided by 2 the remainder is 1, then: Answer: 43 43 ÷ 7 = 6 r 1 43 ÷ 2 = 21 r 1

1098765433 will have a remainder of 1.

Any integer can be divided by 1 without remainder.